You have two nails: Nail #1 has a cross-sectional area of 0.007 cm^2, and Nail #2 has a corss-sectional area of 0.09 cm^2. You hit Nail #1 into a block of wood with 1 N of force, and it goes 1cm deep.
How much force (in Newtons) do you need to hit Nail #2 with in order to make go 1cm into the block of wood?You have two nails: Nail #1 has a cross-sectional area of 0.007 cm^2, and Nail #2 has a corss-sectional area o?
The pressure impressed by the hammer in the first nail is:
P = F/A = 1/0.007 = 142.86 N/cm虏
You must give the same pressure to the second nail so:
P = F1/A1 =%26gt; F1 = 142.86*0.09 = 12.86 NYou have two nails: Nail #1 has a cross-sectional area of 0.007 cm^2, and Nail #2 has a corss-sectional area o?
P1/P2= (F1/A1)/ (F2/A2) = h1/h2= 1
F1A2/ F2A1 =1
1 X 0.09/ F2 X 0.007 = 1
F= 0.09/0.007 = 12.8 N
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